# Practice Questions on Critical PathLogical Reasoning

Common Information

A significant amount of traffic flows from point S to point T in the one-way street network shown below. Points A, B, C, and D are junctions in the network, and the arrows mark the direction of traffic flow. The fuel cost in rupees for travelling along a street is indicated by the number adjacent to the arrow representing the street.

Motorists travelling from point S to point T would obviously take the route for which the total cost of travelling is the minimum. If two or more routes have the same least travel cost, then motorists are indifferent between them. Hence, the traffic gets evenly distributed among all the least cost routes.

The government can control the flow of traffic only by levying appropriate toll at each junction. For example, if a motorist takes the route S-A-T (using junction A alone), then the total cost of travel would be Rs. 14 (i.e. Rs. 9 + Rs. 5) plus the toll charged at junction A.

## Section-1: Critical Path Question - 21

 Q21. Common Information Question: 4/5 If the government wants to ensure that the traffic at S gets evenly distributed along streets from S to A, from S to B, and from S to D, then a feasible set of toll charged (in rupees) at junctions A, B, C, and D respectively to achieve this goal is:
 A. 0, 5, 4, 1 B. 0, 5, 2, 2 C. 1, 5, 3, 3 D. 1, 5, 3, 2 E. 0, 4, 3, 2

## Section-1: Critical Path Question - 22

 Q22. Common Information Question: 5/5 The government wants to devise a toll policy such that the total cost to the commuters per trip is minimized. The policy should also ensure that not more than 70 per cent of the total traffic passes through junction B. The cost incurred by the commuter travelling from point S to point T under this policy will be:
 A. Rs. 7 B. Rs. 9 C. Rs. 10 D. Rs. 13 E. Rs. 14

Common Information

Ajay would do five tasks: A, B, C, D and E; starting at 9 am in the morning. A is the first task and takes two hours. B can be done after A is complete and requires 1 hour. Work on C which would take 1 hour can start only after A and B are complete. Ajay can do task D along with B and C and would take 3 hours for that. Activity E with duration of 1 hour can start on completion of A, B, C and D.

## Section-1: Critical Path Question - 23

 Q23. Common Information Question: 1/3 What is the earliest time when Ajay would complete C?
 A. 11 am B. 12 noon C. 1 pm D. 2 pm

## Section-1: Critical Path Question - 24

 Q24. Common Information Question: 2/3 If Ajay takes 2 hours for B and completes other preceding tasks without delay, when can E start?
 A. 12 noon B. 3 pm C. 2 pm D. 1 pm

## Section-1: Critical Path Question - 25

 Q25. Common Information Question: 3/3 What is the earliest time when Ajay can complete all tasks?
 A. 4 pm B. 3 pm C. 2 pm D. 1 pm
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