Aptitude Discussion

Q. |
Two numbers are respectively $20\%$ and $50\%$ more than a third number. The ratio of the two numbers is: |

✖ A. |
2:5 |

✖ B. |
3:5 |

✔ C. |
4:5 |

✖ D. |
5:4 |

**Solution:**

Option(**C**) is correct

Let the third number be $x$.

Then, first number = $120\%$ of $x$= \(\dfrac{120x}{100}=\dfrac{6x}{5}\)

Second number = $150\%$ of $x$ = \(\dfrac{150x}{100}=\dfrac{3x}{2}\)

Ratio of first two numbers = \(\dfrac{6x}{5}:\dfrac{3x}{2}=4:5\)

**Edit:** For an alternative solution, check comment by **Atchayaa.**

**Edit 2:** For yet another alternative approach to reach the solution, check comment by **Sam.**

**Edit 3:** For yet another alternative solution, check comment by **Mukesh.**

**Mukesh**

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**Atchayaa**

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consider the third no as 100

first number is 20% more than 100 means 120

so second number is 50% more than 100 means 150

Now ratio of 1st and 2nd number is 120:150

i.e 4:5...

simple

**Mudit**

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% sign is not visible

Thank you for pointing it out, corrected the mistake.

**Aayush Nigam**

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% sign is not visible in the browser...LAPTOP using chrome

is the website complete mobile based now??.....

Corrected the issue. Yes, now the website is responsive and supports mobile devices.

**Sam**

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Let take three number as 10, 10, 10.

20% of 10=2,

50% of 10=5.

so the ratio is 10+2/10+5

=12/15

=4/5

=4:5

**Tenzing**

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Thrice the square of a number is 10 times another number.

What is the ratio of the first no to the second no.?

any other data?

Let No. $C=1$

so, $B=1.2$ and $C=1.5$

$B:C=12:15=4:5$