Data Interpretation Discussion

**Common Information**

A soft drink company prepares drinks of three different flavours - $X$, $Y$ and $Z$. The production (in lakhs) of three flavours over a period of six years has been expressed in the bar graph provided below.

Q. |
What is the difference between the average production of flavour $X$ in 1995, 1996 and 1997 and the average production of flavour $Y$ in 1998, 1999 and 2000? |

✖ A. |
50,000 bottles |

✖ B. |
80,000 bottles |

✖ C. |
2,40,000 bottles |

✔ D. |
5,00,000 bottles |

**Solution:**

Option(**D**) is correct

Average production of flavour $X$ in 1995, 1996 and 1997:

$= \left[\dfrac{1}{3} × (50 + 40 + 55)\right]$

$=\dfrac{145}{3}$ lakh bottles.

Average production of flavour Y in 1998, 1999 and 2000:

$=\left[\dfrac{1}{3} × (55 + 50 + 55)\right]$

$=\dfrac{160}{3}$ lakh bottles.

⇒ Difference $=\left[\dfrac{160}{3} – \dfrac{145}{3}\right]$

$=\dfrac{15}{3}$

= 5 lakh bottles

= **5,00,000 bottles**

**Lee**

*()
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Thank you for pointing it out, modified the question.

I dont think the unit had been mentioned anywhere in the chart or the sum. This makes the answer confusing.