# Moderate Ratios & Proportion Solved QuestionAptitude Discussion

 Q. $A$, $B$ and $C$ play cricket. $A$'s runs are to $B$'s runs and $B$'s runs are to $C$'s as $3:2$. They get altogether 342 runs. How many runs did $A$ make?
 ✔ A. 162 ✖ B. 108 ✖ C. 72 ✖ D. None

Solution:
Option(A) is correct

$A:B=3:2=9:6$

$B:C=3:2=6:4$ (making B equal)

Therefore, $A:B:C$ = $9:6:4$

Therefore, the runs made by A= $\dfrac{9}{19}\times 342=162$