# Moderate Ratios & Proportion Solved QuestionAptitude Discussion

 Q. Points $A$ and $B$ are both in the line segment $PQ$ and on the same side of its midpoint. $A$ divides $PQ$ in the ratio $2:3$, and $B$ divides $PQ$ in the ratio $3:4$. If $AB=2$, then the length of $PQ$ is:
 ✔ A. 70 ✖ B. 75 ✖ C. 80 ✖ D. 85

Solution:
Option(A) is correct

Let $PA=2x$ and $AB=3x$

and $PB=3y$ and $BQ=4y$

$PB:BQ=3:4$

$PA:QA=2:3$

$PQ=5x=7y$

$x=7/5$.....(i)

From equation (i) and (ii),

Now, $AB=PQ−PA−BQ=7y−4y−2x$

$⇒ 3y−2x=2$ -------------- (ii)

$y=10$ and Hence, $PQ$ = 70.

## (4) Comment(s)

Raj Karan
()

in easy language to make it comprehensive

we are given the ratio as 4:3(7 unit) and 3:2(5 unit) but total distance is same in both the cases so let it be 35(i.e 7*5) now

4:3= 20:15

and 3:2=21:14

by plotting a line you easily figured out that AB here is 1 unit(15-14=1)

value of 1 unit = 2(given AB length)

value of 35 unit = 35*2(=70)ans

Kruthi M
()

let x=length of PQ.

A divides PQ in 2:3. So PA=(2/5)x

B divides PQ in 3:4. So PB = (3/7)x

Now PA = PB-AB.

(2/5)x = (3/7)x -2

solving we get x = 70

Bhargavi Bhat
()

It should be QA=3x instead of AB=3x

Saikiran
()

One more easier way. (Eliminating from the options)

Take 2:3 = 5 parts, now 70/5=14 (which means 28:42) is one ratio.

Take 3:4 = 7 parts, now 70/7=10 (which means 30:40) is other ratio.

Diff between 30-28 = 2 (dist AB is 2). We get it