Aptitude Discussion

Q. |
Three beakers have capacity of 250ml, 650ml and 200ml. 682 ml of Juice is poured into them so that the same fraction of each is filled. The volume filled in the largest beaker will be: |

✖ A. |
415 ml |

✔ B. |
403 ml |

✖ C. |
400 ml |

✖ D. |
424 ml |

**Solution:**

Option(**B**) is correct

As the beaker filled by the same fractions,

\(\dfrac{p}{250}=\dfrac{q}{650}=\dfrac{r}{200}=\dfrac{p+q+r}{250+650+200}\)

Thus $p+q+r=682$

$⇒ q$ = **403 ml**.

**Needtosuccess**

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**Mmm**

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250+650+200 = 1100

hence largest beaker is q, and q capacity is 650.

so, q=650/1100 = 0.59

0.59*682= 403

q=403

**Asfandyar**

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anyone who can help me out regarding the explanation?

**Tanjida**

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What the fuck is this solution?

**Siddhant**

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i dont understant ur calculatiion

**Nikhil**

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I cant understand the solution please explain me clearly...and how we can get'q' value plzzz?

**Niket**

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Crisp and nice solution. Liked it very much.

keep doing a great job.

What you understand there can you explain it

total capacity of 3 beakers = 250+ 650+200=1100

the fraction of largest beaker total= 650/1100=13/22

out of the 682 ml, 650 ml beaker is filled with= 13/22 x650=403