# Moderate Ratios & Proportion Solved QuestionAptitude Discussion

 Q. $20%$ of the students in a class failed in an examination. Out of the students who failed, $75%$ were males. Male students who failed constitute $90%$ of the economically poor students in the class. What is the ratio of the number of economically poor students to the number of students in the class?
 ✖ A. $1:4$ ✖ B. $1:5$ ✖ C. $5:6$ ✔ D. $1:6$

Solution:
Option(D) is correct

Let the total number of students in the class be '$t$'

Let total number of students in the class who are economically poor be '$p$'

Total number of students who failed = $\dfrac{t}{5}$

Total number of male students who failed

$\dfrac{3}{4} \times \dfrac{t}{5}=\dfrac{9p}{10}$

$\Rightarrow \dfrac{p}{t}=\dfrac{1}{6}$

$\Rightarrow \dfrac{\text{Number of economically poor students}}{\text{Number of Students}}=\dfrac{1}{6}=1:6$