Ratios & Proportion

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$20%$ of the students in a class failed in an examination. Out of the students who failed, $75%$ were males. Male students who failed constitute $90%$ of the economically poor students in the class. What is the ratio of the number of economically poor students to the number of students in the class?









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Option(D) is correct

Let the total number of students in the class be '$t$'

Let total number of students in the class who are economically poor be '$p$'

Total number of students who failed = \(\dfrac{t}{5}\)

Total number of male students who failed 

\(\dfrac{3}{4} \times \dfrac{t}{5}=\dfrac{9p}{10}\)

\(\Rightarrow \dfrac{p}{t}=\dfrac{1}{6}\)

\(\Rightarrow \dfrac{\text{Number of economically poor students}}{\text{Number of Students}}=\dfrac{1}{6}=1:6\)

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