Time and Work

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To complete a piece of work $A$ and $B$ take 8 days, $B$ and $C$ 12 days. $A$, $B$ and $C$ take 6 days. $A$ and $C$ will take :


7 Days


7.5 Days


8 Days


8.5 Days

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Option(C) is correct

Given $(A+B)$'s  one day’s work = \(\dfrac{1}{8}\)

$(B+C)$'s  one day’s work = \(\dfrac{1}{12}\)

$(A+B+C) $'s 1 day’s work = \(\dfrac{1}{6}\)

Work done by $A$, alone:

$=(A+B+C)$'s 1 day’s work - $(B+C)$'s  one day’s work

$= \dfrac{1}{6} - \dfrac{1}{12}$


Work done by $C$, alone:

$=(A+B+C) $'s 1 day’s work - $(A+B)$'s  one day’s work

$= \dfrac{1}{6} - \dfrac{1}{8}$


$(A+C)$'s one day’s work:



$(A+C)$ will take $\textbf{8 days}$ to complete the work together.

Edit:For an alternative solution, check comment by Manpreet Kunnath.

(10) Comment(s)

Abhijeet Panchalwar

Take LCM then check the option which divisible by 24 LCM value I, E 8days


A+B = 1/8th of the work

B+C = 1/12th of the work

A+B+C = 1/6th of the work

C= 1/6-1/8 =1/24

A= 1/6- 1/12 = 1/12

C+A = 1/24+ 1/12 = 3/24 i.e., 1/8th of the work

So togather they will take 8days

Hope you guys know the basics

Pavan Kumar

Given (1/A+1/B)=1/8


(1/A+1/B+1/C)=1/6 Then

2* (1/A+1/B+1/C)=2/6 => (1/A+1/C)=2/6-1/8-1/12 =>

After solving above one we will get


so 8 days required to complete the work if A and C are worked to gether


How 1/A can be work done in one day ? Pls do reply

Manpreet Kunnath

$A+B+C=6$ ..... (1)

$A+B=8$ ..... (2)

Replacing (2) in (1)


Hence, $C=2$ (Ignoring the negative symbol)

$B+C=12$ ..... (3)

replacing (3) in (1)


Hence, $A=6$ (Ignoring the negative symbol)

So adding the two results

$A+C = 6+2$

$= \textbf{8 days}$

Suhail Ahmed

We have formula for this:


Simply solve for $=ZX$

S Malik

@Shireen like $A+B=8$ SO $A=8-B$ and so on


Tried but could not work out the calculation, any help please.

Muhammad Shehroz

Keep it simple. Put values of $A+B$ and $B+C$ in $A+B+C=6$ equation to get values of $C$ and $A$ simultaneously.


Can you please elaborate more?