Permutation-Combination
Aptitude

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Q.

How many words can be formed by re-arranging the letters of the word $ASCENT$ such that $A$ and $T$ occupy the first and last position respectively?

 A.

$5!$

 B.

$4!$

 C.

$6! – 2!$

 D.

$6!/2!$

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Solution:
Option(B) is correct

As $A$ and $T$ should occupy the first and last position, the first and last position can be filled in only one following way.

$A\; \_\;\_ \;\_ \;\_ \;T$

The remaining $4$ positions can be filled in $4!$ Ways by the remaining words $(S,C,E,N,T).$

Hence by rearranging the letters of the word $ASCENT$ we can form:

$1\times4! = \textbf{4! Words.}$


(1) Comment(s)


ROHIT
 ()

in the question it has mentioned the word "rearrange" so i think we have to subtract 1 from !4 that is !4-1