Aptitude Discussion

Q. |
How many words can be formed by re-arranging the letters of the word $ASCENT$ such that $A$ and $T$ occupy the first and last position respectively? |

✖ A. |
$5!$ |

✔ B. |
$4!$ |

✖ C. |
$6! – 2!$ |

✖ D. |
$6!/2!$ |

**Solution:**

Option(**B**) is correct

As $A$ and $T$ should occupy the first and last position, the first and last position can be filled in only one following way.

$A\; \_\;\_ \;\_ \;\_ \;T$

The remaining $4$ positions can be filled in $4!$ Ways by the remaining words $(S,C,E,N,T).$

Hence by rearranging the letters of the word $ASCENT$ we can form:

$1\times4! = \textbf{4! Words.}$

**ROHIT**

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in the question it has mentioned the word "rearrange" so i think we have to subtract 1 from !4 that is !4-1