# Easy Permutation-Combination Solved QuestionAptitude Discussion

 Q. How many words can be formed by re-arranging the letters of the word $ASCENT$ such that $A$ and $T$ occupy the first and last position respectively?
 ✖ A. $5!$ ✔ B. $4!$ ✖ C. $6! – 2!$ ✖ D. $6!/2!$

Solution:
Option(B) is correct

As $A$ and $T$ should occupy the first and last position, the first and last position can be filled in only one following way.

$A\; \_\;\_ \;\_ \;\_ \;T$

The remaining $4$ positions can be filled in $4!$ Ways by the remaining words $(S,C,E,N,T).$

Hence by rearranging the letters of the word $ASCENT$ we can form:

$1\times4! = \textbf{4! Words.}$

## (1) Comment(s)

ROHIT
()

in the question it has mentioned the word "rearrange" so i think we have to subtract 1 from !4 that is !4-1