Aptitude Discussion

Q. |
There are $6$ equally spaced points $A,B,C,D,E$ and $F$ marked on a circle with radius $R$. How many convex pentagons of distinctly different areas can be drawn using these points as vertices? |

✖ A. |
${^6P_5}$ |

✖ B. |
$1$ |

✖ C. |
$5$ |

✔ D. |
$\text{None of these}$ |

**Solution:**

Option(**D**) is correct

Since, all the points are equally spaced; hence the area of all the convex pentagons will be same.

**Raj Singh**

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**Shubham**

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if the points have not been equally spaced then what w be the answer plz tell..

If the points have not been equally spaced then we will get the 1 pantagons have the same area.

if the points have not been equally spaced then at most, 6 pentagons of distinctively different areas could be formed, leaving 1 point each time for creating each pentagon

**Neha**

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though all the pentagons have the same area. The answer should be 1

The answer should be 0 because there is no way where we can draw 2 pentagons of distinctly different areas. For e.g. if the question is "how many ways you can create circles of distinctly different area on a plane of 4 points". Answer it's just not possible.