Permutation-Combination
Aptitude

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Q.

There are $6$ equally spaced points $A,B,C,D,E$ and $F$ marked on a circle with radius $R$.

How many convex pentagons of distinctly different areas can be drawn using these points as vertices?

 A.

${^6P_5}$

 B.

$1$

 C.

$5$

 D.

$\text{None of these}$

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Solution:
Option(D) is correct

Since, all the points are equally spaced; hence the area of all the convex pentagons will be same.


(5) Comment(s)


Raj Singh
 ()

The answer should be 0 because there is no way where we can draw 2 pentagons of distinctly different areas. For e.g. if the question is "how many ways you can create circles of distinctly different area on a plane of 4 points". Answer it's just not possible.



Shubham
 ()

if the points have not been equally spaced then what w be the answer plz tell..


RAKESH
 ()

If the points have not been equally spaced then we will get the 1 pantagons have the same area.

Ashis
 ()

if the points have not been equally spaced then at most, 6 pentagons of distinctively different areas could be formed, leaving 1 point each time for creating each pentagon


Neha
 ()

though all the pentagons have the same area. The answer should be 1