Permutation-Combination
Aptitude

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Q.

In an examination paper, there are two groups each containing $4$ questions.

A candidate is required to attempt $5$ questions but not more than $3$ questions from any group.

In how many ways can $5$ questions be selected?

 A.

24

 B.

48

 C.

96

 D.

64

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Solution:
Option(B) is correct

$5$ questions can be selected in the following ways:

$2$ question from first group and 3 question from second group

Or

$3$ question from first group and 2 question from second group.

$({^4C_2} × {^4C_3}) + ({^4C_3} × {^4C_2})$

$= 24 + 24$

$=\textbf{48}$


(1) Comment(s)


RAKESH
 ()

Here, we have 2 groups each having 5 questions and condition is we should not attempt more than 3 question from each group so

By using the combination

${^4C_3} \times {^4C_2}+{^4C_2} \times {^4C_3}=48$