Aptitude Discussion

Q. |
12 men cam complete a piece of work in 36 days, 18 women can complete the same piece of work in 60 days. 8 men and 20 women work together for 20 days. If only women were to complete the remaining piece of work in 4 day, how many women would be required? |

✔ A. |
70 |

✖ B. |
28 |

✖ C. |
66 |

✖ D. |
40 |

**Solution:**

Option(**A**) is correct

12 men in 36 days can do a work.

1 man in a day can do \(\dfrac{1}{12\times 36}\)work.

8 men in 20 days can do \(\dfrac{8\times 20}{12\times 36}=\dfrac{10}{27}\) work.

Similarly, we find that 20 women in 20 days can do \(\dfrac{10}{27}\) work.

Remaining work = \(\dfrac{7}{27}\)

Now, because in 60 days a work is done by 20 women.

In 1 day a work done by $20\times 60$ women.

In 4 days \(\dfrac{7}{27}\) work is done by

= \(\dfrac{20\times 60\times 7}{27\times 4}\) = **70 women.**

**HEMANTH**

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60 days work done by 18 women .....but u have taken 20 instead of 18....