# Difficult Time and Work Solved QuestionAptitude Discussion

 Q. $A$ and $B$ undertake to do a piece of work for Rs 600. $A$ alone can do it in 6 days while $B$ alone can do it in 8 days. With the help of $C$, they can finish it in 3 days, Find the share of $C$?
 ✖ A. 70 ✔ B. 75 ✖ C. 80 ✖ D. 85

Solution:
Option(B) is correct

$C$’s one day’s work,

$= \left(\dfrac{1}{3}\right) - \left(\dfrac{1}{6}+\dfrac{1}{8}\right)$

$= \dfrac{1}{24}$

Therefore,

$A:B:C =$ Ratio of their one day’s work = 1/6:1/8:1/24= 4:3:1A$’s share,$= \text{Rs. }600×\dfrac{4}{8}= 300B$’s share,$= \text{Rs. }600×\dfrac{3}{8}= 225C$’s share,$= \text{Rs. } [600-(300+225)]= \textbf{Rs. 75}\$

Edit: For an alternative solution, check comment by Sooraj.

## (1) Comment(s)

Sooraj
()

A's work in a day =1/6 of the work

B's work in a day= 1/8 of the work

Work done by A and B together in a day =(1/6)+(1/8)=7/24

work done by A and B together in 3 days= (7/24)*3=7/8

Remaining work done by c=1-(7/8)=1/8

Share of C =600*(1/8)=75