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$a,b,c,d$ and $e$ are five natural numbers. Find the number of ordered sets $(a,b,c,d,e)$ possible such that $a+b+c+d+e =64$.









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Option(B) is correct

Let assume that there are 64 identical balls which are to be arranged in 5 different compartments (Since $a,b,c,d,e$ are distinguishable) If the balls are arranged in a row. i.e.,

\[o,o,o,o,o,o......(64\text{ balls})\]

We have 63 gaps where we can place a wall in each gap, since we need 5 compartments we need to place only 4 walls.

We can do this in ${^{63}C_4}$ ways.

(2) Comment(s)


how would it became 4 walls for we need (a,b,c,d,e)--five letters..???

Shubham Kumar

So if you add 4 compartments then you will have 5 divisions which will lead to 5 numbers as asked in question