Aptitude Discussion

Q. |
A passenger train takes two hours less for a journey of 300 km if its speed is increased by 5 km/hr from its normal speed. The normal speed is: |

✖ A. |
35 km/hr |

✖ B. |
50 km/hr |

✔ C. |
25 km/hr |

✖ D. |
30 km/hr |

**Solution:**

Option(**C**) is correct

Let the normal speed be '$s$' km/hr

Then new speed = $(s+5)$ km/hr

\(\dfrac{300}{s}-2=\dfrac{300}{s+5}\)

On solving this equation we get:

$s$ = **25 km/hr**

**NerdBird**

*()
*

your equation is wrong. It should be Speed^2+5Speed-750=0

solution are 25 or -30 for that equation.

as speed can not be negative, the solution is 25.

Someone solve: 2s^2+10^2+1500.

*^2 stands for raised to.