Permutation-Combination
Aptitude

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Q.

In how many ways can a leap year have 53 Sundays?

 A.

$^{365}C_7$

 B.

$7$

 C.

$4$

 D.

$2$

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Solution:
Option(D) is correct

In a leap year there are 366 days i.e. $\text{52 weeks + 2 extra days}$.

So, to have 53 Sundays one of these two days must be a Sunday.

This can occur in only 2 ways.

i.e. (Saturday and Sunday) or (Sunday and Monday).

Thus number of ways $=\textbf{2}$


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