Time, Speed & Distance

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The circumference of the front wheel of a cart is 40 ft long and that of the back wheel is 48 ft long. What is the distance travelled by the cart, when the front wheel has done five more revolutions than the rear wheel?


950 ft


1450 ft


1200 ft


800 ft

 Hide Ans

Option(C) is correct

Let the total distance travelled by the cart be $x$ ft



\(\Rightarrow \dfrac{6x-5x}{240}=5\)

⇒ $x$ = 1200 ft

(3) Comment(s)

Akash Bansal

for every revolution of rear wheel, front wheel rotates 1.2 revolutions.

Therefore, front wheel goes 0.2 revolutions more than rear wheel.

-> for 5 more revolutions,

number of revolutions of rear wheel= (1/0.2)x5 = 25 revolutions

distance travelled by cart= 25 x 48= 1200 Ft.


clarity is missing,,,plz clarrify claearly...why dont u measure the front wheel revolutions

Vejayanantham TR

Front = 40

Back = 48

So, 48-40 = 8

8 * 5(rotation) makes =40 ie one rotation of front.

So, for 5 times the rotation of front more than rear ,

48*25 = 1200