Permutation-Combination
Aptitude

 Back to Questions
Q.

The number of ways which a mixed double tennis game can be arranged amongst 9 married couples if no husband and wife play in the same is:

 A.

1514

 B.

1512

 C.

3024

 D.

3028

 Hide Ans

Solution:
Option(B) is correct

As per the question there are 9 married couples and no husband and wife should play in the same game:

We know that in a mixed double match there are two males and two females.

Step I: Two male members can be selected in ${^9C_2} = 36$ ways

Step II: Having selected two male members, 2 female members can be selected in ${^7C_2} = 21$ ways.

Step III: Two male and two female members can arranged in a particular game in 2 ways.

Total number of arrangements,

$ = 36×21×2$

$= \textbf{1512 ways.}$


(1) Comment(s)


Tlemcani
 ()

Other solution :

9P4 / 2 = 3024 / 2 = 1512 ways