# Easy Time, Speed & Distance Solved QuestionAptitude Discussion

 Q. Two identical trains $A$ and $B$ running in opposite direction at same speed tale 2 min to cross each other completely. The number of bogies of $A$ are increased from 12 to 16. How much more time would they now require to cross each other?
 ✖ A. 40 sec ✖ B. 50 sec ✖ C. 60 sec ✔ D. 20 sec

Solution:
Option(D) is correct

Total initial bogies is $12+12 = 24$

Additional bogies $= 16−12 = 4$

24 bogies take 2 minutes.

4 bogies will take:

$=\dfrac{2\times 60}{24}\times 4$

20 sec.

## (3) Comment(s)

Chirag Goyal
()

4 bogies increase in one train is similar to 2 bogies increase in 2 trains each.

so 12 bogies takes 2 mins and 2 bogies will take 1/6 of 2 mins

i.e. 20 sec more.

Ash
()

How did we get 60? In the solution??s

Anita
()

total boggies 24 take 2 min i.e; 120 sec

1 boggie will take 5 sec

therefore 4 boggies will take 5 * 4=20 sec