Aptitude Discussion

Q. |
$X$ and $Y$ start walking towards each other at 10 am at speeds of 3 km/hr and 4 km/hr respectively. They were initially 17.5 km apart. At what time do they meet? |

✖ A. |
2:30 pm |

✖ B. |
11 :30 pm |

✖ C. |
1:30 pm |

✔ D. |
12 :30 pm |

**Solution:**

Option(**D**) is correct

Let after $T$ hours they meet

Then, $3T+4T = 17.5$

$T = 2.5$

Time = 10:00 am + 2.5 hour = **12:30 pm**

**Nitin Singh**

*()
*

Sorry its 2.5 hrs instead of 2.5s

Simply we can solve these type of questions ..

Total distance/ total speed(x+y)

17.5/(3+4) = 2.5s