Aptitude Discussion

Q. |
A car driver driving in fog, passes a pedestrian who was walking at the rate of 2km/h in the same direction. The pedestrian could see the car for 6 min and it was visible to him up to a distance of 0.6 km. The speed of the car would be : |

✔ A. |
8 km/h |

✖ B. |
800 m/h |

✖ C. |
200 m/h |

✖ D. |
15 km/h |

**Solution:**

Option(**A**) is correct

Traveller distance in 6 min = \(\dfrac{2}{60}\times 6=\dfrac{2}{10}\)

Total distance in 6 min = \(\dfrac{2}{10}+\dfrac{6}{10}=\dfrac{8}{10}\)

Speed =\(\dfrac{8}{10}\times 10\)

= **8 km/hr**

**Muhammad Jawad Ali**

*()
*

Relative Speed = Distance / Time

Let speed of car be x

x - 2 = 0.6 / (6/60)

x - 2 = 0.6/0.1

x = 6+2

x = 8

Which is right answer.