Time, Speed & Distance
Aptitude

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Q.

A car driver driving in fog, passes a pedestrian who was walking at the rate of 2km/h in the same direction. The pedestrian could see the car for 6 min and it was visible to him up to a distance of 0.6 km. The speed of the car would be :

 A.

8 km/h

 B.

800 m/h

 C.

200 m/h

 D.

15 km/h

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Solution:
Option(A) is correct

Traveller distance in 6 min = \(\dfrac{2}{60}\times 6=\dfrac{2}{10}\)

Total distance in 6 min = \(\dfrac{2}{10}+\dfrac{6}{10}=\dfrac{8}{10}\)

Speed =\(\dfrac{8}{10}\times 10\)

8 km/hr


(1) Comment(s)


Muhammad Jawad Ali
 ()

Relative Speed = Distance / Time

Let speed of car be x

x - 2 = 0.6 / (6/60)

x - 2 = 0.6/0.1

x = 6+2

x = 8

Which is right answer.