Time, Speed & Distance
Aptitude

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Q.

A monkey tries to ascend a greased pole 14 m high. He ascends 2 m in first two minutes and slips 1 m in alternate minute. If he continues to ascend in this fashion, how long does he take to reach the top?

 A.

26 min

 B.

24 min

 C.

22 min

 D.

25 min

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Solution:
Option(D) is correct

In every two minutes he is able to ascend 1 m. In this fashion he ascends up to 12 m because when he reaches at the top he does not slip down. Thus, up to 12 m he takes $12\times 2 = 24$ min. and for the last 2 m he takes 1 m.

Therefore, total time taken by him is $24+1$ = 25 min to reach the top


(3) Comment(s)


Rajshekar
 ()

in the question it is given that monkey ascends $2 m in first two minutes and slips 1 m in alternate minute...so in the first two minutes he climbs 2m and then slips 1m in next minute.....so in 3 min it becomes 2-1=1m..So effectively he takes 3min to climb 1m...so to climb 12m he takes 12*3=36m+remaining 2m he climbs in 2 min and then no slipping since he reached his target....

Therefore total time time taken=$12*3+2=38 minutes.



Anshu
 ()

If he climbs up in 2 min and slips down in 1 min then total time to climb 1m should be 3 min not 2min



SIPRA LENKA
 ()

the question over here should be , the monkey ascends 2m in one minute and descends 1m in the next minute