Aptitude Discussion

Q. |
The Ghaziabad-Hapur-Meerut EMU and the Meerut-Hapur-Ghaziabad EMU start at the same time from Ghaziabad and Meerut and proceed towards each other at 16 km/hr and 21 km/hr respectively. When they meet, it is found that one train has travelled 60 km more than the other. The distance between two stations is: |

✖ A. |
445 km |

✔ B. |
444 km |

✖ C. |
440 km |

✖ D. |
450 km |

**Solution:**

Option(**B**) is correct

The two trains start simultaneously. Let they meet after a time ‘$t$’.

The train that has covered 60 km more must be the faster of the two.

Hence:

$60=(21–16)×t$

$⇒ t=12$ hours.

Since they are traveling towards each other, total distance is the sum of the distances travelled by the two trains individually.

Total distance = $16\times12+21\times12$ = **444 Km**