Time, Speed & Distance
Aptitude

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Q.

The Ghaziabad-Hapur-Meerut EMU and the Meerut-Hapur-Ghaziabad EMU start at the same time from Ghaziabad and Meerut and proceed towards each other at 16 km/hr and 21 km/hr respectively. When they meet, it is found that one train has travelled 60 km more than the other. The distance between two stations is:

 A.

445 km

 B.

444 km

 C.

440 km

 D.

450 km

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Solution:
Option(B) is correct

The two trains start simultaneously. Let they meet after a time ‘$t$’.

The train that has covered 60 km more must be the faster of the two. 

Hence:

$60=(21–16)×t$

$⇒ t=12$ hours.

Since they are traveling towards each other, total distance is the sum of the distances travelled by the two trains individually.

Total distance = $16\times12+21\times12$ = 444 Km


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