Aptitude Discussion

Q. |
In a 3600 m race around a circular track of length 400m, the faster runner and the slowest runner meet at the end of the fourth minute, for the first time after the start of the race. All the runners maintain uniform speed throughout the race. If the faster runner runs at thrice the speed of the slowest runner. Find the time taken by the faster runner to finish the race. |

✖ A. |
36 minute |

✔ B. |
24 minute |

✖ C. |
16 minute |

✖ D. |
12 minute |

**Solution:**

Option(**B**) is correct

As, the faster runner is thrice as fast as the slowest runner, the faster runner would have completed three rounds by the time the slowest runner completes one round.

And that is their second meeting.

Their first meeting takes place after the fastest runner takes 4 min to complete one and the half round.

\(400\times \dfrac{3}{2}=600\) m

⇒He takes \(\dfrac{3600}{600}\times 4=24\)**minutes** to finish the race.

**Venka**

*()
*

how do u calculate that he completed "one and half round" in 4min?