Aptitude Discussion

Q. |
In a charity show tickets numbered consecutively from 101 through 350 are placed in a box. What is the probability that a ticket selected at random (blindly) will have a number with a hundredth digit of 2? |

✖ A. |
0.285 |

✔ B. |
0.40 |

✖ C. |
100/249 |

✖ D. |
99/250 |

**Solution:**

Option(**B**) is correct

250 numbers between 101 and 350 i.e. $n(S) = 250$

$n(E) = 100^{th}$ digits of $2= 299-199 = 100$

$P(E) = \dfrac{n(E)}{n(S)}$

$= \dfrac{100}{250}$

$= \textbf{0.40}$

**VShank**

*()
*

It's 250 only (both 101 and 350 are included). Had we left 101, it would have been 249 tickets.

how 250 number will be in between 101 to 350 ?, its 249 only.