# Moderate Percentages Solved QuestionAptitude Discussion

 Q. When processing flower-nectar into honeybees' extract, a considerable amount of water gets reduced. How much flower-nectar must be processed to yield 1kg of honey, if nectar contains $50%$ water, and the honey obtained from this nectar contains $15%$ water?
 ✖ A. 1.5 kgs ✔ B. 1.7 kgs ✖ C. 3.33 kgs ✖ D. None of these

Solution:
Option(B) is correct

Flower-nectar contains $50\%$ of non-water part.

In honey this non-water part constitutes $85\% (100-15)$.

Therefore $0.5X$ Amount of flower-nectar = $0.85X$ Amount of honey = $0.85\times 1$ kg

Therefore amount of flower-nectar needed

$=\left(\dfrac{0.85}{0.5}\right)\times 1$

$=1.7$ kg

## (7) Comment(s)

Babar
()

50% of 100g is 50 g. if we are to get 1 kg honey we have to have 2 kg raw material because there is 50% water. there are also 15% additional water contents so we have to have more than 2 kg raw material. the given answers are wrong.

Azex
()

Doubt.

Extraction process--> Nector(+50%water) --> Honey(+15%water)--> Honey (pure).

End result is 1 Kg honey.

That means if we go one step up, before its extraction it will contain 15% water as well. So now total quantity:

X-15% of X = 1kg honey.

==> .85X = 1

X= 1/.85 ~ 1.176 Kg (Honey plus water)

Now this mixture was extracted from Nector-water mixture.

let us assume it is extracted from X kg of flower nector.

Therefore,

X- 50% of X = 1.176

.5X = 1.176

=> X = 2.352 Kg

Amit
()

i also got this answer but it is correct or not?

PPatel
()

Are there any other different method to solve this question ?

Param
()

As of now no other substitute becoz it is already simple. Let's make it simpler with some verbal concepts.

1. Honey in Nectar = Honey in honeybee = Honey we got. i.e no loss of honey anywhere only the proportion of water kept changing at different stage.

2. The value of honey at all stages is equal . so calculate the value at all three stages at keep them equal.

3. First stage - Honey is 50% of something.say, Value= 0.5X

4. Second stage - Honey is 85% of something. say, Value =0.85X

5. Last stage - Honey is 1 Kg. (Given)

so, 0.5X=0.85X=1kg. X=1.7 Kg (Pretty Obvious will me more than the honey)

Hope it helps.

Salman
()

this is a good place for the preparation of aptitude tests.

Khirodsaikia
()

Please, include all the subjects which are important for ssc exam