Aptitude Discussion

Q. |
A salesman sells two kinds of trousers: cotton and woollen. A pair of cotton trousers is sold at $30\%$ profit and a pair of woollen trousers is sold at $50\%$ profit. The salesman has calculated that if he sells $100\%$ more woollen trousers than cotton trousers, his overall profit will be $45\%$. However, he ends up selling $50\%$ more cotton trousers than woollen trousers. What will be his overall profit? |

✖ A. |
$37.5\%$ |

✔ B. |
$40\%$ |

✖ C. |
$41\%$ |

✖ D. |
$42.33\%$ |

**Solution:**

Option(**B**) is correct

Let the cost price of 1 cotton trouser and 1 woollen trouser be ‘$C$’ and ‘$W$’ respectively.

**Case I:** Number of woollen trousers sold is $100\%$ more than cotton trousers.

Let us calculate profit keeping one unit of a cotton trouser.

\(1.3C+1.5\times 2\times W=1.45(C+2W)\)

\(\Rightarrow0.15C=0.1W \)

\(\Rightarrow3C=2W\)

**Case II:** Number of cotton trousers sold is $50\%$ more than woollen trousers.

Here, we will calculate sales price keeping one unit of a cotton trouser as we did in the case I. Now as per the condition given, cotton trousers sold is $50\%$ more than woollen trousers.

$\Rightarrow$ for every woollen trouser $1.5$ $\left(=\dfrac{3}{2}\right)$ cotton trousers are being sold.

$\Rightarrow$ for every cotton trouser $\dfrac{2}{3}$ $\left(=\dfrac{1}{3/2}\right)$ woollen trousers are being sold.

\(S.P.=1.3C+1.5\times \dfrac{2W}{3}\)

\(\Rightarrow S.P.=1.3C+W=2.8C\)

\(\Rightarrow CP=C+\dfrac{2}{3}\times W\)

\(=2C\)

**Profit**

\(=\dfrac{2.8C-2C}{2C}\times 100\)

\(=\textbf{40%}\)

**Anu**

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**Arun**

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Why is $CP=C+(2/3)W = 2C$

Shouldn't it be $CP=C+W=C+(3/2)C=2.5C$ ?

No, it shouldn't be. CP is calculated keeping ONE unit of $C$ and since condition says, number of cotton trousers sold is 50% more than woollen trousers, which means for every $1 C$ there will be $\frac{2}{3}W$

In case 1 how is it 1.45??please someone tell