# Easy Averages Solved QuestionAptitude Discussion

 Q. A Batsman makes a score of 87 runs in the 17th inning and thus increases his average by 3. Find his average after 17th inning.
 ✖ A. 40 ✔ B. 39 ✖ C. 52 ✖ D. 55

Solution:
Option(B) is correct

Let the average after 17th innings = $x$

Then average after 16th innings = $(x-3)$

Therefore $16(x-3) + 87 = 17x$

Therefore $x = 39$

Edit: For a quick allternative solution, check comment by Sravan Reddy.

## (9) Comment(s)

Deramyncmaype
()

TtsKbEPnjt rani ki mast chudai

Williamhoave
()

T.Huft buy laminine low from 29 usd USA +19492854745 Lamiderm in Hollywood Huft USA +19492854745 Huft, USA Sкуpe tatyana.huft3.

Sudarsanakapoor
()

17 ×3 = 51 ( increase by 3) we do substrate with 87 so for ex- if decrease by 3 we do add 87 in this increase by 3

51 - 87 =36

After 17th inning means 36 +3 = 39

If before 17th inning means 36-3 =33

Kelsiekeeda
()

Why there is so lot of spam on your website?!

Where is exit?!

Harshit Varshney
()

17th inning score= old avg (avg before 17th inning)+increase*no.of participant

87=x+3*16

x=39 old avg before 17th inning

as question said there is increase in avg due to 17th inning score by 3

so new avg = 39+3=42

Sravan Reddy
()

One quick way to do it with mind for these type of problems (in less than 10 secs):

=> He was able to increase average by 3. That means he gave 3 runs to all his previous innings. So answer is $87 - (3 \times 16) = 87-48 = 39!!$

$\textbf{P.S.}$ If you did not understand the splitting 3 runs to all other innings here is an example.

Let the scores for 3 innings be 3,3,3 and fourth innings the average got raised to 4 by scoring 7.

That can be split as if he scored the average runs in the latest innings and distributed 1 run to all the previous innings.

So, the scores instead of 3, 3, 3, 7 will be 4, 4, 4, 4.

Sorry, if I confused you more but hope you will like it once you master this art of splitting :)

Gokul
()

Great Brother...Great Work...thank you a lot...

Sachin
()

Mohan Dand
()

let avg after 17th ings $=x$

therefore avg after 16th ings $=(x-3)$

let total runs after 16th ings $=T$

now,avg after 16th ings =:

$\Rightarrow$ total runs/no.of ings

$\Rightarrow \dfrac{T}{16}=(x-3)$

$\Rightarrow$ now $T=16(x-3)$

now avg after 17th ings=:

$\Rightarrow \dfrac{\text{total runs}}{\text{no. of innings}}$

$\Rightarrow T+\dfrac{87}{17}=x$

$\Rightarrow$ substitute $T$ value

$\Rightarrow 16(x-3)+\dfrac{87}{17}=x$

$\Rightarrow$ after simplification we get $x=39$