# Moderate Averages Solved QuestionAptitude Discussion

 Q. The average wages of a worker during a fortnight comprising 15 consecutive working days was Rs.90 per day. During the first 7 days, his average wages was Rs.87/day and the average wages during the last 7 days was Rs.92 /day. What was his wage on the $8^{th}$ day?
 ✖ A. 83 ✖ B. 92 ✖ C. 90 ✔ D. 97

Solution:
Option(D) is correct

The total wages earned during the 15 days that the worker worked :

$= 15 \times 90 = Rs. 1350.$

The total wages earned during the first 7 days = $7 \times 87$ = Rs. 609.

The total wages earned during the last 7 days = $7 \times 92$ = Rs. 644.

Total wages earned during the 15 days = wages during first 7 days + wage on $8^{th}$ day + wages during the last 7 days.

$1350 = 609+$ wage on $8^{th}$ day $+ 644$

wage on $8^{th}$ day = $1350 - 609 - 644$ = Rs. 97

## (3) Comment(s)

Harshit Varshney
()

8th day=90-3*7+2*2

()

7 days the wage was Rs. 3 less so means 21 less than 90

87-90 = 3 * 7 =21

7 days the wage was Rs. 2 more than 90

92-92=2 * 7 = 14

so 21-14=7

7 we need more in order to get an average of 90

therefore, 90+7=97