Aptitude Discussion

Q. |
Two teams Arrogant and Overconfident are participating in a cricket tournament. The odds that team Arrogant will be champion is 5 to 3, and the odds that team Overconfident will be the champion is 1 to 4. What are the odds that either Arrogant or team Overconfident will become the champion? |

✖ A. |
3 to 2 |

✖ B. |
5 to 2 |

✖ C. |
6 to 1 |

✔ D. |
33 to 7 |

**Solution:**

Option(**D**) is correct

As probability of a both the teams (Arrogant and Overconfident) winning simultaneously is zero.

\(P(A\cap O)=0\)

\(P(A\cap B)=P(A)+P(B)\)

\(=\dfrac{5}{8}+\dfrac{1}{5}\)

\(=\dfrac{33}{40}\)

So required odds will be **33 : 7**

**Verma**

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**Mahak**

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It should be A union B and not A intersection B in the explanation.

**Anubhav Singh**

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we have to find the odds in favour not the probability.

so 40-33=7

odds in favour= favourable outcome/unfavourable.

33/7 or 33:7

**Preethu**

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How did 33:7 occur?

It should be 23:17 because probability for either A win or O win should be 23/40.