# Easy Probability Solved QuestionAptitude Discussion

 Q. Two teams Arrogant and Overconfident are participating in a cricket tournament. The odds that team Arrogant will be champion is 5 to 3, and the odds that team Overconfident will be the champion is 1 to 4. What are the odds that either Arrogant or team Overconfident will become the champion?
 ✖ A. 3 to 2 ✖ B. 5 to 2 ✖ C. 6 to 1 ✔ D. 33 to 7

Solution:
Option(D) is correct

As probability of a both the teams (Arrogant and Overconfident) winning simultaneously is zero.

$P(A\cap O)=0$

$P(A\cap B)=P(A)+P(B)$

$=\dfrac{5}{8}+\dfrac{1}{5}$

$=\dfrac{33}{40}$

So required odds will be 33 : 7

## (3) Comment(s)

Mahak
()

It should be A union B and not A intersection B in the explanation.

Anubhav Singh
()

we have to find the odds in favour not the probability.

so 40-33=7

odds in favour= favourable outcome/unfavourable.

33/7 or 33:7

Preethu
()

How did 33:7 occur?