Probability
Aptitude

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Q.

Two teams Arrogant and Overconfident are participating in a cricket tournament. The odds that team Arrogant will be champion is 5 to 3, and the odds that team Overconfident will be the champion is 1 to 4. What are the odds that either Arrogant or team Overconfident will become the champion?

 A.

3 to 2

 B.

5 to 2

 C.

6 to 1

 D.

33 to 7

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Solution:
Option(D) is correct

As probability of a both the teams (Arrogant and Overconfident) winning simultaneously is zero.

\(P(A\cap O)=0\)

\(P(A\cap B)=P(A)+P(B)\)

\(=\dfrac{5}{8}+\dfrac{1}{5}\)

\(=\dfrac{33}{40}\)

So required odds will be 33 : 7


(4) Comment(s)


Verma
 ()

It should be 23:17 because probability for either A win or O win should be 23/40.



Mahak
 ()

It should be A union B and not A intersection B in the explanation.



Anubhav Singh
 ()

we have to find the odds in favour not the probability.

so 40-33=7

odds in favour= favourable outcome/unfavourable.

33/7 or 33:7



Preethu
 ()

How did 33:7 occur?