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From a bag containing 4 white and 5 black balls a man drawn 3 balls at random. What are the odds against these balls being black?









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Option(B) is correct

Probability of all three balls being black



Probability that three balls are not black



Hence, odds against these ball being black



(2) Comment(s)

Sudhanva Dixit

Firstly they have asked the odds 'against', that means that (1-P(all Black)).

Coming to your question, It means that in 37/42 cases all the balls are not black. The probability of 2 black & 1 white, 1 Black & 2 white and all three white combined makes 37/42.


Probability that three balls are not black is given as 37/42. It means that the potability that all three balls are white is 37/42. How it is possible?

Since the number of white balls are less than black balls, its probability should be less. Also, calculating the probability of all balls being white = 1/21.

Can some one explain.