Probability
Aptitude

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Q.

In a race where 12 cars are running, the chance that car $X$ will win is 1/6, that $Y$ will win is 1/10 and that $Z$ will win is 1/8. Assuming that a dead heat is impossible. Find the chance that one of them will win.

 A.

47/120

 B.

1/480

 C.

1/160

 D.

1/240

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Solution:
Option(A) is correct

Required probability $=P(X)+P(Y)+P(Z)$ (all the events are mutually exclusive

\(=\dfrac{1}{6}+\dfrac{1}{10}+\dfrac{1}{8}\)

\(=\dfrac{47}{120}\)


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