# Difficult Tabular Data Solved QuestionData Interpretation Discussion

Common Information

In a Class X Board examination, ten papers are distributed over five Groups – PCB, Mathematics, Social Science, Vernacular and English. Each of the ten papers is evaluated out of 100. The final score of a student is calculated in the following manner.

First, the Group Scores are obtained by averaging marks in the papers within the Group. The final score is the simple average of the Group Scores.

The data for the top ten students are presented below. (Dipan’s score in English Paper II has been intentionally removed in the table).

Note: B or G against the name of a student respectively indicates whether the student is a boy or a girl.

Table below can be scrolled horizontally

 PCB Group Math'sGroup Social ScienceGroup VernacularGroup EnglishGroup Name of the student Phy. Chem. Bio. Hist. Geo. Paper I Paper II Paper I Paper II Final Score Ayesha(G) 98 96 97 98 95 93 94 96 96 98 96.2 Ram(B) 97 99 95 97 95 96 94 94 96 98 96.1 Dipan(B) 98 98 98 95 96 95 96 94 96 ?? 96.0 Sagnik(B) 97 98 99 96 96 98 94 97 92 94 95.9 Sanjiv(B) 95 96 97 98 97 96 92 93 95 96 95.7 Shreya(G) 96 89 85 100 97 98 94 95 96 95 95.5 Joseph(B) 90 94 98 100 94 97 90 92 94 95 95.0 Agni(B) 96 99 96 99 95 96 82 93 92 93 94.3 Pritam(B) 98 98 95 98 83 95 90 93 94 94 93.9 Tirna(G) 96 98 79 99 85 94 92 91 87 96 93.7
 Q. Common Information Question: 2/5 Students who obtained Group Scores of at least 95 in every group are eligible to apply for a prize. Among those who are eligible, the student obtaining the highest Group Score in Social Science Group is awarded this prize. The prize was awarded to:
 ✖ A. Shreya ✖ B. Ram ✖ C. Ayesha ✔ D. Dipan ✖ E. No one from the top ten

Solution:
Option(D) is correct

From the table we can observe that only Dipan is eligible to apply for the prize.

So Dipan gets the prize.

Hence, option D.

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