Data Interpretation Discussion

**Common Information**

Answer the questions on the basis of the information given below.

In a school, there are four chemical laboratories namely Lab 1, Lab 2, Lab 3 and Lab 4. There are only six types of acids that are available in these laboratories. The following table provides information about the number of bottles of each type of acid in each of these laboratories.

Every bottle of acid in the chemical laboratories is further categorized on the basis of its capacity under one or the other of the five different categories namely ‘S’, ‘M’, ‘L’, ‘XL’ and ‘XXL’.

The following chart provides information about the number of bottles of acids in each of the mentioned categories (on the basis of its capacity) as a percentage of the total number of bottles of acids in these laboratories.

Q. |
In Lab 1, the total number of bottles of acids in the category XL as a percentage of the total number of bottles of acids in Lab 1 cannot be less than |

✖ A. |
2% |

✖ B. |
3% |

✔ C. |
4% |

✖ D. |
5% |

✖ E. |
6% |

**Solution:**

Option(**C**) is correct

Given that In Lab 2 as well as Lab 3, the number of bottles of acids in the category XL as a percentage of the total number of bottles of acids in the respective laboratories is not more than 1%.

Total number of bottles in these laboratories $= 2400$

A maximum of 6 bottles each in Lab 2 and Lab 3 can be in the category XL.

Also, a maximum of 688 bottles in Lab 4 can be in the category XL.

Total number of XL bottles,

$=2400×\dfrac{300}{100}= 720$

So, in Lab 1, the number of bottles of acid in the category XL cannot be less than:

$=720 - 6 - 6 - 688 = 20$

⇒ Required percentage,

$=\dfrac{20}{500}×100$

$= \textbf{4%}$

**Edit:** Correct answer choice has been changed to option(C) from option(E) [Calculation is unchanged], as notified by **Piyush.**

**Swathi**

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bcz usne bola hai lab 2 and lab 3 m XL category 1% se jyada ni hogi 609*1/100=6 and 603*1/100=6

**Piyush**

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so the answer is 4% not 6% option (c)

Thank you Piyush for letting me know, I've corrected it.

**Yaswanth**

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How can we get a maximum of 688 bottles in lab 4

It's given in the problem, check first chart.

If you sum up all the bottles it's $688$ only $(=117+107+129+99+75+161)$

hey, why are we deducting 6 botthles from each category? 1% of 720 is 7.2 so why not 7?