# Difficult Pie Charts Solved QuestionData Interpretation Discussion

Common Information

Answer the questions on the basis of the information given below.

The following Pie-Chart provides information about the marks obtained by six students A, B, C, D, E and F in four different subjects P, Q, R and S. The marks obtained by each of the students in subject P is indexed to the maximum marks that can be obtained in subject P. This holds true for the other three subjects as well.

For example, if the maximum marks that can be obtained in subject P is ‘40k’, then the marks obtained in subject P by student A is 15k, by student B is 20k and so on. This holds true for the marks obtained by the students in the other three subjects as well.

The marks obtained by A in subject P is not less than that obtained by him in subject Q or subject R, but not more than that obtained by him in subject S. This holds true for the marks obtained by each of the other 5 students as well.

 Q. Common Information Question: 1/5 If the marks obtained by A in subjects Q and R is the same, then the maximum marks that can be obtained in subject Q as a percentage of the maximum marks that can be obtained in subject R is:
 ✖ A. $50/3$ ✖ B. $250/3$ ✔ C. $100/3$ ✖ D. $25$

Solution:
Option(C) is correct

Let the maximum marks which can be obtained in the subjects P, Q, R and S be 40p, 50q, 60r and 80s respectively.

From the given information we can conclude that:

$15p≥20q, 20p≥10q, 25p≥15q, 10p ≥18q, 25p≥32q$ and $30p≥ 12q$

⇒ $p ≥ 1.8q$ -------- (i)

$15p≥8r, 20p≥16r, 25p≥20r$, $10p≥24r, 25p≥10r$ and $30p≥20r$

⇒ $p≥2.4r$ -------- (ii)

$15p≤25s, 20p≤15s$, $25p≤20s$, $10p≤30s$, $25p≤10s$ and $30p≤35s$

⇒ $p≤ 0.4s$ -------- (iii)

The marks obtained by A in subjects Q and R are $20q$ and $8r$ respectively.

⇒ $20q = 8r$

⇒ $q/r = 2/5$,

Required percentage:

$= \dfrac{50q}{60r}×100$

$=\dfrac{50}{60} × \dfrac{2}{5} × 100$

$= 100/3$