Aptitude Discussion

Q. |
A bag contains 2 red, 3 green and 2 blue balls are to be drawn randomly. What is the probability that the balls drawn contain no blue ball? |

✖ A. |
5/7 |

✔ B. |
10/21 |

✖ C. |
2/7 |

✖ D. |
11/21 |

**Solution:**

Option(**B**) is correct

2 balls can be drawn in the following ways:

1 red, 1 green or 2 red or 2 green

Required probability:

\(=\left(\dfrac{^2C_1\times ^3C_1}{^7C_2}\right)+\dfrac{^2C_2}{^7C_2}+\dfrac{^3C_2}{^7C_2}\)

\(=\dfrac{6}{21}+\dfrac{1}{21}+\dfrac{3}{21}\)

\(=\dfrac{10}{21}\)

**VTG**

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there is no mention of 2 balls drawn in the question.Admin please correct.Thank you