Algebra
Aptitude

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Q.

The ratio of ages of a father and son is $17:7$ respectively. 6 years ago the ratio of their ages was $3:1$ respectively. What is the father's present age?

 A.

64

 B.

51

 C.

48

 D.

54

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Solution:
Option(B) is correct

Let the present age of the father and son be $17x$ years and $7x$ years.

According to Question:

\(\dfrac{(17x-6)}{(7x-6)}=\dfrac{3}{1}\)

Father's present age $=17x= 51$ years


(3) Comment(s)


Girish
 ()

it is given

ratio is 17:7



Sravan Reddy
 ()

Killing it: (took 5 sec)

ratio - 17:1. so father age is a multiple of 17. only possible value in options - 51. No need to even recheck :)


Sravan
 ()

Sorry, the ratio is 17:7. Still the method is same.