Aptitude Discussion

Q. |
The ratio of ages of a father and son is $17:7$ respectively. 6 years ago the ratio of their ages was $3:1$ respectively. What is the father's present age? |

✖ A. |
64 |

✔ B. |
51 |

✖ C. |
48 |

✖ D. |
54 |

**Solution:**

Option(**B**) is correct

Let the present age of the father and son be $17x$ years and $7x$ years.

According to Question:

\(\dfrac{(17x-6)}{(7x-6)}=\dfrac{3}{1}\)

Father's present age $=17x= 51$** years**

**Girish**

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**Sravan Reddy**

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Killing it: (took 5 sec)

ratio - 17:1. so father age is a multiple of 17. only possible value in options - 51. No need to even recheck :)

Sorry, the ratio is 17:7. Still the method is same.

it is given

ratio is 17:7