# Easy Algebra Solved QuestionAptitude Discussion

 Q. A farmer has decided to build a wire fence along one straight side of his property. For this, he planned to place several fence posts at 6 m intervals, with posts fixed at both ends of the side. After he bought the posts and wire, he found that the number of posts he had bought was 5 less than required. However, he discovered that the number of posts he had bought would be just sufficient if he spaced them 8 m apart. What is the length of the side of his property and how many posts did he buy?
 ✖ A. 100 m, 15 ✖ B. 100 m, 16 ✖ C. 120 m, 15 ✔ D. 120 m, 16

Solution:
Option(D) is correct

Let the length of the side of the property be $x$ m and $y$ be the number of posts bought.

When the space between polls is 8 m,

The number of poles

$=\dfrac{x}{8}+1$

When space between poles is 6m,
The number of poles

$=\dfrac{x}{6}+1=y+5$

On solving both of the equations we get,

$x= 120$ m and $y = 16$

## (1) Comment(s)

Hemu Kumar
()

if u assume 9mt length... posts fixed with 3mt interval

so takes total 4 post..(9/3=3 3+1=4)

check ur options only 120mt divide by 6 so 120/6=20 gives 21 post but 5less so 16 post

Option D