Algebra
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Q.

A farmer has decided to build a wire fence along one straight side of his property. For this, he planned to place several fence posts at 6 m intervals, with posts fixed at both ends of the side. After he bought the posts and wire, he found that the number of posts he had bought was 5 less than required. However, he discovered that the number of posts he had bought would be just sufficient if he spaced them 8 m apart. What is the length of the side of his property and how many posts did he buy?

 A.

100 m, 15

 B.

100 m, 16

 C.

120 m, 15

 D.

120 m, 16

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Solution:
Option(D) is correct

Let the length of the side of the property be $x$ m and $y$ be the number of posts bought. 

When the space between polls is 8 m,

The number of poles

\(=\dfrac{x}{8}+1\)

When space between poles is 6m,
The number of poles

\(=\dfrac{x}{6}+1=y+5\)

On solving both of the equations we get,

$x= 120$ m and $y = 16$


(1) Comment(s)


Hemu Kumar
 ()

if u assume 9mt length... posts fixed with 3mt interval

so takes total 4 post..(9/3=3 3+1=4)

check ur options only 120mt divide by 6 so 120/6=20 gives 21 post but 5less so 16 post

Option D