Algebra
Aptitude

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Q.

Abhishek had a certain number of Re 1 coins, Rs 2 coins and Rs 10 coins. If the number of Re 1 coins he had is six times the number of Rs 2 coins Abhishek had, and the total worth of his coins is Rs 160, find the maximum number of Rs 10 coins Abhishek could have had.

 A.

12

 B.

10

 C.

8

 D.

6

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Solution:
Option(A) is correct

If the Abhishek had $x$ Re 1, $y$ Rs 2 coins and $z$ Rs 10 coins, the total value of coins he had: 

$=x(1)+y(2)+z(10)=x+2y+10z=160$

Since, $6y=x$

Thus, $8y+10z=160$ i.e $8y$ is a multiple of 10 i.e. $y=5$ or $y=10$ 

i.e. $(x,y,z)=(30,5,12)$ or $(60,10,8)$

Thus, the maximum value of '$z$' is $\textbf{12}$

Edit: Thank you Sujal Padhiyar, corrected the typo.


(2) Comment(s)


Sujal Padhiyar
 ()

Here, for $y=10$, value of $z$ will be 8 and not 18.


Deepak
 ()

Thank you for letting me know the error, corrected it.