# Moderate Algebra Solved QuestionAptitude Discussion

 Q. Abhishek had a certain number of Re 1 coins, Rs 2 coins and Rs 10 coins. If the number of Re 1 coins he had is six times the number of Rs 2 coins Abhishek had, and the total worth of his coins is Rs 160, find the maximum number of Rs 10 coins Abhishek could have had.
 ✔ A. 12 ✖ B. 10 ✖ C. 8 ✖ D. 6

Solution:
Option(A) is correct

If the Abhishek had $x$ Re 1, $y$ Rs 2 coins and $z$ Rs 10 coins, the total value of coins he had:

$=x(1)+y(2)+z(10)=x+2y+10z=160$

Since, $6y=x$

Thus, $8y+10z=160$ i.e $8y$ is a multiple of 10 i.e. $y=5$ or $y=10$

i.e. $(x,y,z)=(30,5,12)$ or $(60,10,8)$

Thus, the maximum value of '$z$' is $\textbf{12}$

Edit: Thank you Sujal Padhiyar, corrected the typo.

## (2) Comment(s)

Here, for $y=10$, value of $z$ will be 8 and not 18.