Algebra
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Q.

Three persons Suresh, Devesh and Prashant were born on different days in the same year. If the date and month of birth of Suresh, Devesh and Prashant are numerically equal, then what could be the minimum difference in the ages of youngest and oldest in days?

 A.

56

 B.

60

 C.

61

 D.

62

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Solution:
Option(C) is correct

To have the minimum differences in the ages of the oldest and youngest. 

One of them should be born in February.

Also the other two should be born in March and April of January and March.

Difference between the youngest and the oldest is the number of days from

2nd Feb. to 4th Mar.: 

$=(26+31+4)=61$

or, 1st Jan to 3rd Mar. $=30+28+3=$ 61 days.


(5) Comment(s)


Aayan
 ()

Question is vague. Please correct.



Shubham Paul
 ()

question is not clear



Ravi
 ()

Hello,

Can someone please provide a simple explanation to the question and the answer



Ravish
 ()

56 is possible..if we take 5th feb 4th march and 3rd april..so num of days is $23+31+2=56$


Sujal Padhiyar
 ()

Hello Ravish,

Here they have mentioned that month & date will be numerically equal. so you can't take 5-feb & 4-march.

If you are going with Feb then - it must be 2/2 nd same will be for another choices, like March- 3/3, April- 4/4, May-5/5 and so on.