# Difficult Algebra Solved QuestionAptitude Discussion

 Q. In a cricket match, Team $A$ scored 232 runs without losing a wicket. The score consisted of byes, wides and runs scored by two opening batsmen: Ram and Shyam. The runs scored by the two batsmen are 26 times wides. There are 8 more byes than wides. If the ratio of the runs scored by Ram and Shyam is $6:7$, then the runs scored by Ram is:
 ✖ A. 88 ✔ B. 96 ✖ C. 102 ✖ D. 112

Solution:
Option(B) is correct

Let the number of runs scored by byes, wides and runs be $x, y$ and $z$ respectively:

$x+y+z=232$ -------- (i)

The runs scored by the two batsmen are 26 times the wides:

$z=26y$--------- (ii)

There are 8 more byes than wides:

$x=y+8$ -------- (iii)

Substituting equations (iii) and (ii) in equation (i),

we get, $y=8,z=208$

The runs scored by Ram and Shyam were in the ratio $6 : 7$

Let the runs scored by Ram be 6r and by Shyam be 7r.

$13r=208$

$⇒ r=16$

Runs scored by Ram $=16×6=96$

## (1) Comment(s)

Deepak
()

Ram = R, Shyam = S, Wide = W.

$R + S = 26*W$

$B = W + 8$

$W + 26*W + W + 8 = 232$

=> $28*W = 224$

=> $W = 8$

$R + S = 208$

$6x + 7x = 208$

$x = 16$

=> $R = 6x$

$= \textbf{96}$

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