# Difficult Algebra Solved QuestionAptitude Discussion

 Q. Because of the economic slowdown, a multinational company curtailed some of the allowances of its employees. Rashid, the marketing manager of the company whose monthly salary has been reduced to Rs 42,000 is unable to cut more on his expenditure. He finds that there is a deficit of Rs 2,000 between his earning and expenses in the first month. This deficit, because of inflationary pressure, will keep on increasing by Rs 500 every month. Rashid has a saving of Rs 60,000 which will be used to fill the deficit. After his savings get exhausted, Rashid would start borrowing from his friends. How soon will he start borrowing?
 ✖ A. $10^{th}$ months ✖ B. $11^{th}$ months ✖ C. $12^{th}$ months ✔ D. $13^{th}$ months

Solution:
Option(D) is correct

Let the Rashid 's savings will last till '$n$' months.

$\Rightarrow \dfrac{n}{2}[2\times 2000+(n-1)500]=60,000$

[Expenditure every month increases by 500 rupees]

$\Rightarrow n^2+7n-200=0$

$n=12.38$

⇒ Rashid after Kartik's mother asked him to get the vegetables, milk and butter from the market and gave him the money in the denominator of 1 Rupee, 2 Rupee and 5 Rupee coins.

Kartik first goes to the grocery shop to buy vegetables. At the grocery shop he gives half of his 5 Rupee coins in return receives the same number of 1 Rupee coins.

Next he goes to the dairy shop to buy milk and butter and gives all 2 Rupee coins and in return get thirty 5 Rupee coins, which increase the number of five rupee coins by 75% more than the original number.

If the number of 1 rupee coins now is 50, the number of 1 rupee and 5 rupee coins originally were will start borrowing money from his friends.

## (2) Comment(s)

ViP
()

n^2+7n−240=0 and not 2000

Chandler Monica
()

2000+2500+3000+3500+4000+4500+5000+5500+6000+6500+7000+7500 = 56500 upto 12 months, from 13 th month he ll start borrowing as it crosses 60k savings