Algebra
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Q.

In a group, each person has at most two $A$. No person has less than three $C$. Considering all the persons in the group there are more $A$ than $G$, more $G$ than $B$ and more $B$ than persons. Find the minimum number of persons in the groups?

 A.

4

 B.

5

 C.

3

 D.

2

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Solution:
Option(C) is correct

Let the total number of person be '$p$'.

Hence, $a>g>b>p$

Going by the choices, $p$ must be at least 2, If $p=2,a≤4$

But to satisfy the above inequality, $a$ must be at least 5.

Hence p is not equal to 2.

If $p =3$, to satisfy the inequality above, $a$ must be at least 6.

As, $a≤6$. It can be satisfied.

Minimum value of $f =3$


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