The sum of three digit number is subtracted from the number.
The resulting number is always:
divisible by 6
not divisible by 6
divisible by 9
not divisible by 9
Solution:Option(C) is correct
Let the three digit number be $439$
Sum of digits $=16$
Difference $= 439-16 = 423$ which is divisible by 9.
Error(s) Found !!!
Arun (Dec 25'16 at 20:06)
if we take no as 999 then it get divisible by both 6 and 9.
The question reads 'always'!
DUDE (Sep 25'16 at 10:47)
This is the property which will be true for all. Doesn't matter how may digits you take it will be always divisible by 9.
ie.2,3,4,5,6...and so on
Riya (May 07'13 at 18:13)
It holds for 153 too..
sum of digits $=9.$
subtracting 9 from 153 you get 144 which is divisible by 9
it holds for 6 also which is also given in the options
Shreya (May 07'13 at 17:54)
what if we take the example 153?
Deepak (Apr 28'13 at 10:08)
Let the $3$ digit number be: $XYZ$
As per the question we have to find the divisibility of number $P$ (let),
$\Rightarrow P=9 \times (11X+Y)$
which is divisible by 9.
So if the sum of three digit number is subtracted from the number. The resulting number is always divisible by 9.
ur answer also not divisible by 6 at all.
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