If $N=2^3×3^4$ , $M= 2^2×3×5$, then find the number of factors of $N$ that are common with the factors of $M$.
Solution:Option(B) is correct
The factors that are common must also be the factors of $HCF(N,M)$
$HCF(N,M) = 2^2×3$
Number of factors of $2^2×3 = (2+1)(1+1) = 6$
So there are 6 factors that are common to both.
Error(s) Found !!!
Shashiii Ghanekar (Jul 28'17 at 09:52)
Therefore 6 is the common factor of 648 and 60 i.e. N and M
Saikiran (Sep 13'16 at 10:05)
Taking the common values 2^2*3, we get 12.. factors of 12 are 1,2,3,4,6,12.. 6 factors common to M & N.. Is it right too??.. I have a doubt
Abhay (May 28'13 at 13:45)
The answer, I reckon, should be 6. The calculation of HCF is wrong.
Shreya (May 08'13 at 13:12)
is there some problem in the soln as while taking out the hcf we take the less powers of common prime factors
Fill out the name first.
Posting as #name, Edit Details
To write Maths use $ or $$ delimiters. (TeX)Ex: $ax^2+bx+c=0$.
Help us keep afloat. Consider making a small contribution.
To appreciate the effort Lofoya.com is putting, Please like our page and help us spread the word.