Aptitude Discussion

Q. |
A can contains a mixture of two liquids A and B in the ratio 7:5 when 9 litres of mixture are drawn off and the can is filled with B, the ratio of A and B becomes 7:9. How many litres of liquid A was contained by the can initially? |

✖ A. |
28 litres |

✔ B. |
21 litres |

✖ C. |
45 litres |

✖ D. |
36 litres |

**Solution:**

Option(**B**) is correct

Suppose the can initially contains $7x$ and $5x$ litres of mixtures A and B respectively.

When 9 litres of mixture are drawn off, quantity of A in mixture left:

$7x-\left(\dfrac{7}{12}\right)\times 9 = 7x -\dfrac{21}{4}$ litres

Similarly quantity of B in mixture left:

$5x-\left(\dfrac{5}{12}\right)\times 9 = 5x -\dfrac{15}{4}$ litres

Therefore ratio becomes:

\begin{align*}

\dfrac{7x-\dfrac{21}{4}}{5x-\dfrac{15}{4}+9}&=\dfrac{7}{9}\\

\Rightarrow \dfrac{28x-21}{20x+21}&=\dfrac{7}{9}\\

\Rightarrow 252x-189&=140x+147\\

\Rightarrow 112x &=336\\

\Rightarrow x&=3

\end{align*}

So the can contained:

$7\times x=7\times 3= 21$ litres of A initially.

**Elamurugan**

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**Sreethi Reddy**

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what abt addition of b??

**Mangesh Kumar**

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what about addition of b

Mangesh, I think the when the ratio becomes $7:9$, there is a typo in the solution.

the $3^{rd}$ equation given should be modified from:

\(\dfrac{7x-(21/4)}{5x-(15/4)}=\dfrac{7}{9}\) to

\(\dfrac{7x-(21/4)}{5x-(15/4)+ \textbf{9}}=\dfrac{7}{9}\)

Which will take us to the correct next step as given in the existing solution.

I guess they will take it into consideration and and update the solution.

I think initial mixture should be, $7+5=12\times 3=36$