Aptitude Discussion

Q. |
It is given that $2^{32} + 1$ is exactly divisible by a certain number. Which one of the following is also divisible by the same number? |

✔ A. |
$2^{96} + 1$ |

✖ B. |
$2^{16} + 1$ |

✖ C. |
$2^{32} + 1$ |

✖ D. |
$2^{64} + 1$ |

**Solution:**

Option(**A**) is correct

If $2^{32} + 1 = a+b$

Since $a^3 + b^3 = (a+b)^3 -3ab(a+b)$

$= (a+b)[(a+b)^2 -3ab]$

So, $a^3 + b^3$ is always divisible by $(a+b)$

**ABHIJEET**

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what is the purpose of this question?.. the logic given is irrelevant