# Easy Number System Solved QuestionAptitude Discussion

 Q. It is given that $2^{32} + 1$ is exactly divisible by a certain number. Which one of the following is also divisible by the same number?
 ✔ A. $2^{96} + 1$ ✖ B. $2^{16} + 1$ ✖ C. $2^{32} + 1$ ✖ D. $2^{64} + 1$

Solution:
Option(A) is correct

If $2^{32} + 1 = a+b$

Since $a^3 + b^3 = (a+b)^3 -3ab(a+b)$

$= (a+b)[(a+b)^2 -3ab]$

So, $a^3 + b^3$ is always divisible by $(a+b)$

## (2) Comment(s)

V J
()

The option (c) should not be given as that is also a correct answer!

ABHIJEET
()

what is the purpose of this question?.. the logic given is irrelevant