Number System
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Q.

It is given that $2^{32} + 1$ is exactly divisible by a certain number. Which one of the following is also divisible by the same number?

 A.

$2^{96} + 1$

 B.

$2^{16} + 1$

 C.

$2^{32} + 1$

 D.

$2^{64} + 1$

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Solution:
Option(A) is correct

If $2^{32} + 1 = a+b$

Since $a^3 + b^3 = (a+b)^3 -3ab(a+b)$

$= (a+b)[(a+b)^2 -3ab]$

So, $a^3 + b^3$ is always divisible by $(a+b)$


(1) Comment(s)


ABHIJEET
 ()

what is the purpose of this question?.. the logic given is irrelevant