# Easy Number System Solved QuestionAptitude Discussion

 Q. The number 3072 is divisible by both 6 and 8. Which one of the following is the first integer larger than 3072 that is also divisible by both 6 and 8?
 ✖ A. 3084 ✖ B. 3086 ✖ C. 3090 ✔ D. 3096

Solution:
Option(D) is correct

Any number divisible by both 6 and 8 must be a multiple of the least common multiple of the two numbers, which is 24.

Hence, any such number can be represented as $24 n$ .

If 3072 is one such number and is represented as $24n$, then the next such number should be:

$24(n + 1) = 24n + 24 = 3072 + 24 =$ 3096.

## (2) Comment(s)

Abhijeet
()

check the divisibility of 8 for each of the options.. only one satisfies(the correct answer)

Sarang Kulkarni
()

The next number divisible by 6 and 8 will current number + L.C.M of 6 and 8 i.e. 3072+24=2096