The number 3072 is divisible by both 6 and 8.
Which one of the following is the first integer larger than 3072 that is also divisible by both 6 and 8?
Solution:Option(D) is correct
Any number divisible by both 6 and 8 must be a multiple of the least common multiple of the two numbers, which is 24.
Hence, any such number can be represented as $24 n$ .
If 3072 is one such number and is represented as $24n$, then the next such number should be:
$24(n + 1) = 24n + 24 = 3072 + 24 =$ 3096.
Error(s) Found !!!
Abhijeet (Jan 20'17 at 20:21)
check the divisibility of 8 for each of the options.. only one satisfies(the correct answer)
Sarang Kulkarni (Aug 05'16 at 11:17)
The next number divisible by 6 and 8 will current number + L.C.M of 6 and 8 i.e. 3072+24=2096
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