Aptitude Discussion

Q. |
The ratio, in which tea costing Rs. 192 per kg is to be mixed with tea costing Rs. 150 per kg so that the mixed tea when sold for Rs. 194.40 per kg, gives a profit of 20%. |

✖ A. |
1:2 |

✔ B. |
2:5 |

✖ C. |
3:5 |

✖ D. |
3:7 |

**Solution:**

Option(**B**) is correct

CP of first tea = Rs. 192 per kg.

CP of Second tea = Rs. 150 per kg.

Mixture is to be sold in Rs. 194.40 per kg, which has included 20% profit. So,

SP of Mixture = Rs. 194.40 per kg.

Let the CP of Mixture be Rs. $X$ per kg. Therefore,

$X + 20\% \text{ of } X = \text{SP}$

$\dfrac{6X}{5} = 194.40$

$6X = 194.40 \times 5$

$X = \text{Rs. }162 \text{ per kg.}$

Let $N$ kg of first tea and $M$ kg of second tea to be added.

Now, Using Alligation, We get,

Thus,

$\dfrac{N}{M}=\dfrac{162-150}{192-162}$

$\dfrac{N}{M}=\dfrac{12}{30}$

$\dfrac{N}{M}=\dfrac{2}{5}$

$\Rightarrow \textbf{N : M = 2 : 5}$

**Neelam**

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*

**Surya**

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*

How 6X/5 came I don't understand

gain = 20%

selling price per kg = 194.40

therefore cost price = (100/120)*194.40

= 162

the ratio is (192-162): (162-150)

30 : 12

5 : 2