Critical Path
Logical Reasoning

 Back to Questions

Common Information

There are seven cities P, Q, R, S, T, U, and V. The table below shows all the possible direct routes to and fro between any two of the cities. It also gives both the Air as well as the Land route distances (in miles) between those cities and the time required (in hrs) for the respective journeys. A person on any one of the above seven places can travel to any one of the remaining 6 places using Air or Land route only. The person can change his/her mode of transport (Air/Land) at any of the above seven places.

Table below can be scrolled horizontally

Direct
Routes
Air Distance
(in miles)
Air Time
(in hrs)
Land Distance
(in miles)
Land Time
(in hrs)
P – Q 1100 3 900 6
P – S 2200 6 2400 10
P – R 700 2 1000 6
Q – U 1800 5 2200 11
Q – T 800 3 1100 6
R – T 1000 3 1400 10
S – T 800 3 1000 5
S – V 2200 6 2800 14
T – V 2200 6 3000 15
U – V 800 4 1200 6
Q.

Common Information Question: 3/4

If the air route and the land route fares are $\$$35 and $\$$25 respectively per 100 miles for a passenger, which is the cheapest route from Q to S via R?

 A.

QTRPS by Land

 B.

QPRTS by Air

 C.

QPRTS by Land

 D.

Both (A) and (B)

 E.

None of these

 Hide Ans

Solution:
Option(C) is correct

Total fare = Route distance $\times$ Fare per mile

∴ The fares for the given routes can be calculated as follows:

QPRTS by Air $= (1100 + 700 + 1000 + 800) \times \dfrac{35}{100}$ $= \$ 1260$

QPRTS by Land $= (900 + 1000 + 1400 + 1000) \times \dfrac{25}{100}$ $= \$ 1075$

QTRPS by Land $= (1100 + 1400 + 1000 + 2400) \times \dfrac{25}{100}$ $= \$ 1475$

Hence, option C is the correct choice.


(0) Comment(s)